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6.53x^2+8.62x-7.51=0
a = 6.53; b = 8.62; c = -7.51;
Δ = b2-4ac
Δ = 8.622-4·6.53·(-7.51)
Δ = 270.4656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.62)-\sqrt{270.4656}}{2*6.53}=\frac{-8.62-\sqrt{270.4656}}{13.06} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.62)+\sqrt{270.4656}}{2*6.53}=\frac{-8.62+\sqrt{270.4656}}{13.06} $
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